opt:合托优化
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@@ -871,7 +871,9 @@ public class HandheldServiceImpl implements HandheldService {
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try {
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// 4. 查询源托盘的所有物料信息
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List<SchBaseVehiclematerialgroup> allSourceMaterials = iSchBaseVehiclematerialgroupService.selectByVehicleCode(sourceVehicleCode);
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if(CollectionUtils.isEmpty(allSourceMaterials)){
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throw new BadRequestException("源托盘中不存在物料,无法合托");
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}
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// 7. 执行合托操作
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for (int i = 0; i < selectedMaterials.size(); i++) {
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@@ -896,6 +898,19 @@ public class HandheldServiceImpl implements HandheldService {
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}
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}
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if(allSourceMaterials.size() == selectedMaterials.size()) {
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//源托盘点位变成空载具状态
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iSchBasePointService.update(Wrappers.lambdaUpdate(SchBasePoint.class)
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.eq(SchBasePoint::getVehicle_code, sourceVehicleCode)
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.set(SchBasePoint::getPoint_status, "1"));
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}
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//目标托盘变成有货状态
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iSchBasePointService.update(Wrappers.lambdaUpdate(SchBasePoint.class)
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.eq(SchBasePoint::getVehicle_code, targetVehicleCode)
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.set(SchBasePoint::getPoint_status, "2"));
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// 8. 判断是否需要入库:如果两个托盘都不在货架上,则需要入库
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boolean needStoreIn = ObjectUtil.isEmpty(sourcePoint) && ObjectUtil.isEmpty(targetPoint);
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